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							| 12345678910 | \begin{frage}[3]
Finden Sie $\LoesungsMenge{}_{(x;y)}$:
\gleichungZZ{(x-3)(y+6)}{(x-4)(y+3)}{(y-3)(x+6)}{(x-4)(y+3)}
  $$\LoesungsMenge{}_{(x;y)}=\LoesungsRaumLang{x=1.5 \textrm{ und } y=1.5}$$
  \platzFuerBerechnungen{10.8}
\end{frage}
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